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241434331253 is a prime number
BaseRepresentation
bin1110000011011010011…
…0111000100001110101
3212002011222021210120122
43200312212320201311
512423424142100003
6302525143341325
723304652645403
oct3406646704165
9762158253518
10241434331253
1193434427575
123a95ba51845
13199c85b074b
14b984d7a473
156430d33238
hex38369b8875

241434331253 has 2 divisors, whose sum is σ = 241434331254. Its totient is φ = 241434331252.

The previous prime is 241434331247. The next prime is 241434331261. The reversal of 241434331253 is 352133434142.

241434331253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206718443569 + 34715887684 = 454663^2 + 186322^2 .

It is a cyclic number.

It is not a de Polignac number, because 241434331253 - 228 = 241165895797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241434331753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120717165626 + 120717165627.

It is an arithmetic number, because the mean of its divisors is an integer number (120717165627).

Almost surely, 2241434331253 is an apocalyptic number.

It is an amenable number.

241434331253 is a deficient number, since it is larger than the sum of its proper divisors (1).

241434331253 is an equidigital number, since it uses as much as digits as its factorization.

241434331253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 35.

Adding to 241434331253 its reverse (352133434142), we get a palindrome (593567765395).

The spelling of 241434331253 in words is "two hundred forty-one billion, four hundred thirty-four million, three hundred thirty-one thousand, two hundred fifty-three".