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242024211131 is a prime number
BaseRepresentation
bin1110000101100111000…
…1000110001010111011
3212010201002020210122112
43201121301012022323
512431131144224011
6303103454442535
723325404564663
oct3413161061273
9763632223575
10242024211131
11937073a2aaa
123aaa550344b
1319a90874bb1
14b9dd44b1a3
156467a0258b
hex3859c462bb

242024211131 has 2 divisors, whose sum is σ = 242024211132. Its totient is φ = 242024211130.

The previous prime is 242024211119. The next prime is 242024211139. The reversal of 242024211131 is 131112420242.

242024211131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 242024211131 - 210 = 242024210107 is a prime.

It is a super-2 number, since 2×2420242111312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 242024211097 and 242024211106.

It is not a weakly prime, because it can be changed into another prime (242024211139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121012105565 + 121012105566.

It is an arithmetic number, because the mean of its divisors is an integer number (121012105566).

Almost surely, 2242024211131 is an apocalyptic number.

242024211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

242024211131 is an equidigital number, since it uses as much as digits as its factorization.

242024211131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 242024211131 its reverse (131112420242), we get a palindrome (373136631373).

The spelling of 242024211131 in words is "two hundred forty-two billion, twenty-four million, two hundred eleven thousand, one hundred thirty-one".