Base | Representation |
---|---|
bin | 1110000101111111001… |
… | …1100100101000100011 |
3 | 212010222010220000002011 |
4 | 3201133303210220203 |
5 | 12431333113222431 |
6 | 303121514133351 |
7 | 23331044664205 |
oct | 3413763445043 |
9 | 763863800064 |
10 | 242125523491 |
11 | 93759600525 |
12 | 3ab13421257 |
13 | 19aa8857b37 |
14 | ba0caa0775 |
15 | 6471865cb1 |
hex | 385fce4a23 |
242125523491 has 2 divisors, whose sum is σ = 242125523492. Its totient is φ = 242125523490.
The previous prime is 242125523477. The next prime is 242125523513. The reversal of 242125523491 is 194325521242.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 242125523491 - 215 = 242125490723 is a prime.
It is a super-3 number, since 3×2421255234913 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (242125523791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121062761745 + 121062761746.
It is an arithmetic number, because the mean of its divisors is an integer number (121062761746).
Almost surely, 2242125523491 is an apocalyptic number.
242125523491 is a deficient number, since it is larger than the sum of its proper divisors (1).
242125523491 is an equidigital number, since it uses as much as digits as its factorization.
242125523491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 40.
The spelling of 242125523491 in words is "two hundred forty-two billion, one hundred twenty-five million, five hundred twenty-three thousand, four hundred ninety-one".
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