Base | Representation |
---|---|
bin | 110111001001000011110100… |
… | …011100010000100101011011 |
3 | 1011210200012221200202100112002 |
4 | 313021003310130100211123 |
5 | 223241331443404400021 |
6 | 2215441525325511215 |
7 | 102040066052432033 |
oct | 6711036434204533 |
9 | 1153605850670462 |
10 | 242515134450011 |
11 | 70300100049a25 |
12 | 23249083a1250b |
13 | a54210489a927 |
14 | 43c5b1bbd48c3 |
15 | 1d085963dd50b |
hex | dc90f471095b |
242515134450011 has 2 divisors, whose sum is σ = 242515134450012. Its totient is φ = 242515134450010.
The previous prime is 242515134449933. The next prime is 242515134450047. The reversal of 242515134450011 is 110054431515242.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 242515134450011 - 230 = 242514060708187 is a prime.
It is not a weakly prime, because it can be changed into another prime (242515134450811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121257567225005 + 121257567225006.
It is an arithmetic number, because the mean of its divisors is an integer number (121257567225006).
Almost surely, 2242515134450011 is an apocalyptic number.
242515134450011 is a deficient number, since it is larger than the sum of its proper divisors (1).
242515134450011 is an equidigital number, since it uses as much as digits as its factorization.
242515134450011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 242515134450011 its reverse (110054431515242), we get a palindrome (352569565965253).
The spelling of 242515134450011 in words is "two hundred forty-two trillion, five hundred fifteen billion, one hundred thirty-four million, four hundred fifty thousand, eleven".
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