Base | Representation |
---|---|
bin | 1110000111100011000… |
… | …1011101110000111111 |
3 | 212012001100002012122102 |
4 | 3201320301131300333 |
5 | 12433212331321341 |
6 | 303231240135315 |
7 | 23344322252621 |
oct | 3417061356077 |
9 | 765040065572 |
10 | 242544401471 |
11 | 93953a9a779 |
12 | 3b00b76753b |
13 | 19b44578c28 |
14 | ba4c57ac11 |
15 | 6498507c9b |
hex | 3878c5dc3f |
242544401471 has 2 divisors, whose sum is σ = 242544401472. Its totient is φ = 242544401470.
The previous prime is 242544401423. The next prime is 242544401483. The reversal of 242544401471 is 174104445242.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-242544401471 is a prime.
It is a super-3 number, since 3×2425444014713 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (242544401401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121272200735 + 121272200736.
It is an arithmetic number, because the mean of its divisors is an integer number (121272200736).
Almost surely, 2242544401471 is an apocalyptic number.
242544401471 is a deficient number, since it is larger than the sum of its proper divisors (1).
242544401471 is an equidigital number, since it uses as much as digits as its factorization.
242544401471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 143360, while the sum is 38.
The spelling of 242544401471 in words is "two hundred forty-two billion, five hundred forty-four million, four hundred one thousand, four hundred seventy-one".
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