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242551520153 = 793070272407
BaseRepresentation
bin1110000111100100110…
…0100111101110011001
3212012001211110212122022
43201321030213232121
512433221142121103
6303232052504225
723344436622035
oct3417114475631
9765054425568
10242551520153
1193958012088
123b01201b075
1319b45b9c177
14ba4d4b11c5
156498e62138
hex3879327b99

242551520153 has 4 divisors (see below), whose sum is σ = 245621792640. Its totient is φ = 239481247668.

The previous prime is 242551520129. The next prime is 242551520173. The reversal of 242551520153 is 351025155242.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-242551520153 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (242551520173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1535136125 + ... + 1535136282.

It is an arithmetic number, because the mean of its divisors is an integer number (61405448160).

Almost surely, 2242551520153 is an apocalyptic number.

It is an amenable number.

242551520153 is a deficient number, since it is larger than the sum of its proper divisors (3070272487).

242551520153 is an equidigital number, since it uses as much as digits as its factorization.

242551520153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3070272486.

The product of its (nonzero) digits is 60000, while the sum is 35.

Adding to 242551520153 its reverse (351025155242), we get a palindrome (593576675395).

The spelling of 242551520153 in words is "two hundred forty-two billion, five hundred fifty-one million, five hundred twenty thousand, one hundred fifty-three".

Divisors: 1 79 3070272407 242551520153