Base | Representation |
---|---|
bin | 110111010000001101000101… |
… | …101101100001000110111111 |
3 | 1011212102011021121120221220102 |
4 | 313100031011231201012333 |
5 | 223322403020243403013 |
6 | 2220455250004111315 |
7 | 102120420202441145 |
oct | 6720150555410677 |
9 | 1155364247527812 |
10 | 243006124200383 |
11 | 7047a355a55525 |
12 | 2330826b39553b |
13 | a5794c10ba03b |
14 | 44017b84d5595 |
15 | 1d16230ebcd58 |
hex | dd0345b611bf |
243006124200383 has 2 divisors, whose sum is σ = 243006124200384. Its totient is φ = 243006124200382.
The previous prime is 243006124200361. The next prime is 243006124200391. The reversal of 243006124200383 is 383002421600342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243006124200383 - 210 = 243006124199359 is a prime.
It is a super-2 number, since 2×2430061242003832 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243006124200683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121503062100191 + 121503062100192.
It is an arithmetic number, because the mean of its divisors is an integer number (121503062100192).
Almost surely, 2243006124200383 is an apocalyptic number.
243006124200383 is a deficient number, since it is larger than the sum of its proper divisors (1).
243006124200383 is an equidigital number, since it uses as much as digits as its factorization.
243006124200383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 38.
The spelling of 243006124200383 in words is "two hundred forty-three trillion, six billion, one hundred twenty-four million, two hundred thousand, three hundred eighty-three".
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