Base | Representation |
---|---|
bin | 100011010111100111011… |
… | …110011111001011000011 |
3 | 22121100122111220120020001 |
4 | 203113213132133023003 |
5 | 304310221223114024 |
6 | 5100324044300431 |
7 | 340413022362034 |
oct | 43274736371303 |
9 | 8540574816201 |
10 | 2430540051139 |
11 | 857871549672 |
12 | 33307ab41717 |
13 | 148278103795 |
14 | 858d2abaa8b |
15 | 43355b2a244 |
hex | 235e779f2c3 |
2430540051139 has 2 divisors, whose sum is σ = 2430540051140. Its totient is φ = 2430540051138.
The previous prime is 2430540051109. The next prime is 2430540051169. The reversal of 2430540051139 is 9311500450342.
It is a balanced prime because it is at equal distance from previous prime (2430540051109) and next prime (2430540051169).
It is a cyclic number.
It is not a de Polignac number, because 2430540051139 - 27 = 2430540051011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2430540051098 and 2430540051107.
It is not a weakly prime, because it can be changed into another prime (2430540051109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1215270025569 + 1215270025570.
It is an arithmetic number, because the mean of its divisors is an integer number (1215270025570).
Almost surely, 22430540051139 is an apocalyptic number.
2430540051139 is a deficient number, since it is larger than the sum of its proper divisors (1).
2430540051139 is an equidigital number, since it uses as much as digits as its factorization.
2430540051139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 2430540051139 in words is "two trillion, four hundred thirty billion, five hundred forty million, fifty-one thousand, one hundred thirty-nine".
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