Search a number
-
+
24310244113 = 31784201423
BaseRepresentation
bin10110101001000000…
…001110001100010001
32022202020000100121121
4112221000032030101
5344241410302423
615100140522241
71520300444161
oct265100161421
968666010547
1024310244113
11a345554241
124865550381
1323a5672b3c
1412689185a1
1597437545d
hex5a900e311

24310244113 has 4 divisors (see below), whose sum is σ = 25094445568. Its totient is φ = 23526042660.

The previous prime is 24310244093. The next prime is 24310244129. The reversal of 24310244113 is 31144201342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 24310244113 - 217 = 24310113041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (24310244143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 392100681 + ... + 392100742.

It is an arithmetic number, because the mean of its divisors is an integer number (6273611392).

Almost surely, 224310244113 is an apocalyptic number.

It is an amenable number.

24310244113 is a deficient number, since it is larger than the sum of its proper divisors (784201455).

24310244113 is an equidigital number, since it uses as much as digits as its factorization.

24310244113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 784201454.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 24310244113 its reverse (31144201342), we get a palindrome (55454445455).

The spelling of 24310244113 in words is "twenty-four billion, three hundred ten million, two hundred forty-four thousand, one hundred thirteen".

Divisors: 1 31 784201423 24310244113