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243112451311 = 261792897383
BaseRepresentation
bin1110001001101010100…
…0011001110011101111
3212020111220222010112101
43202122220121303233
512440343241420221
6303403451315531
723364360511612
oct3423250316357
9766456863471
10243112451311
1194115705a54
123b149a4bba7
1319c05168cb2
14baa3ba8179
1564cd313d91
hex389aa19cef

243112451311 has 4 divisors (see below), whose sum is σ = 243205351312. Its totient is φ = 243019551312.

The previous prime is 243112451261. The next prime is 243112451321. The reversal of 243112451311 is 113154211342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243112451311 - 217 = 243112320239 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 243112451311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243112451321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46446075 + ... + 46451308.

It is an arithmetic number, because the mean of its divisors is an integer number (60801337828).

Almost surely, 2243112451311 is an apocalyptic number.

243112451311 is a deficient number, since it is larger than the sum of its proper divisors (92900001).

243112451311 is an equidigital number, since it uses as much as digits as its factorization.

243112451311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92900000.

The product of its digits is 2880, while the sum is 28.

Adding to 243112451311 its reverse (113154211342), we get a palindrome (356266662653).

The spelling of 243112451311 in words is "two hundred forty-three billion, one hundred twelve million, four hundred fifty-one thousand, three hundred eleven".

Divisors: 1 2617 92897383 243112451311