Base | Representation |
---|---|
bin | 1110001001101010101… |
… | …1110101001110011101 |
3 | 212020111222122210100211 |
4 | 3202122223311032131 |
5 | 12440344004200140 |
6 | 303403522452421 |
7 | 23364401244046 |
oct | 3423253651635 |
9 | 766458583324 |
10 | 243113350045 |
11 | 9411616a205 |
12 | 3b14a204111 |
13 | 19c053c20a7 |
14 | baa3d5d8cd |
15 | 64cd4402ea |
hex | 389aaf539d |
243113350045 has 16 divisors (see below), whose sum is σ = 296997664320. Its totient is φ = 190989961344.
The previous prime is 243113350033. The next prime is 243113350057. The reversal of 243113350045 is 540053311342.
It is an interprime number because it is at equal distance from previous prime (243113350033) and next prime (243113350057).
It is a cyclic number.
It is not a de Polignac number, because 243113350045 - 25 = 243113350013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243113349989 and 243113350016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 163347 + ... + 716176.
It is an arithmetic number, because the mean of its divisors is an integer number (18562354020).
Almost surely, 2243113350045 is an apocalyptic number.
It is an amenable number.
243113350045 is a deficient number, since it is larger than the sum of its proper divisors (53884314275).
243113350045 is an equidigital number, since it uses as much as digits as its factorization.
243113350045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 880524.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 243113350045 its reverse (540053311342), we get a palindrome (783166661387).
The spelling of 243113350045 in words is "two hundred forty-three billion, one hundred thirteen million, three hundred fifty thousand, forty-five".
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