Base | Representation |
---|---|
bin | 110111010001110001100100… |
… | …110100111110110011001111 |
3 | 1011212210110210002101111002211 |
4 | 313101301210310332303033 |
5 | 223331140003212324403 |
6 | 2221021012242531251 |
7 | 102131260030334251 |
oct | 6721614464766317 |
9 | 1155713702344084 |
10 | 243114020433103 |
11 | 70511093624096 |
12 | 23325161666b27 |
13 | a5867277aa421 |
14 | 4406ad212bcd1 |
15 | 1d18e4855706d |
hex | dd1c64d3eccf |
243114020433103 has 16 divisors (see below), whose sum is σ = 270975168465120. Its totient is φ = 216760657084416.
The previous prime is 243114020433091. The next prime is 243114020433133. The reversal of 243114020433103 is 301334020411342.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243114020433103 is a prime.
It is a super-2 number, since 2×2431140204331032 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243114020433133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9702400 + ... + 24090757.
It is an arithmetic number, because the mean of its divisors is an integer number (16935948029070).
Almost surely, 2243114020433103 is an apocalyptic number.
243114020433103 is a deficient number, since it is larger than the sum of its proper divisors (27861148032017).
243114020433103 is a wasteful number, since it uses less digits than its factorization.
243114020433103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33815466.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 243114020433103 its reverse (301334020411342), we get a palindrome (544448040844445).
The spelling of 243114020433103 in words is "two hundred forty-three trillion, one hundred fourteen billion, twenty million, four hundred thirty-three thousand, one hundred three".
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