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243114131123 is a prime number
BaseRepresentation
bin1110001001101010111…
…0110011111010110011
3212020112001010110210122
43202122232303322303
512440344204143443
6303403551320455
723364411006203
oct3423256637263
9766461113718
10243114131123
1194116653026
123b14a52012b
1319c05606776
14baa40c4403
1564cd546968
hex389abb3eb3

243114131123 has 2 divisors, whose sum is σ = 243114131124. Its totient is φ = 243114131122.

The previous prime is 243114131093. The next prime is 243114131167. The reversal of 243114131123 is 321131411342.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 243114131123 - 210 = 243114130099 is a prime.

It is a super-2 number, since 2×2431141311232 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 243114131092 and 243114131101.

It is not a weakly prime, because it can be changed into another prime (243114139123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121557065561 + 121557065562.

It is an arithmetic number, because the mean of its divisors is an integer number (121557065562).

Almost surely, 2243114131123 is an apocalyptic number.

243114131123 is a deficient number, since it is larger than the sum of its proper divisors (1).

243114131123 is an equidigital number, since it uses as much as digits as its factorization.

243114131123 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 26.

Adding to 243114131123 its reverse (321131411342), we get a palindrome (564245542465).

The spelling of 243114131123 in words is "two hundred forty-three billion, one hundred fourteen million, one hundred thirty-one thousand, one hundred twenty-three".