Base | Representation |
---|---|
bin | 11100111110110… |
… | …10100110010001 |
3 | 121221110121001100 |
4 | 32133122212101 |
5 | 444214211213 |
6 | 40042455013 |
7 | 6011312160 |
oct | 1637324621 |
9 | 557417040 |
10 | 243116433 |
11 | 115261a7a |
12 | 69504469 |
13 | 3b4a24a1 |
14 | 244073d7 |
15 | 16524773 |
hex | e7da991 |
243116433 has 12 divisors (see below), whose sum is σ = 401335168. Its totient is φ = 138923640.
The previous prime is 243116431. The next prime is 243116437. The reversal of 243116433 is 334611342.
243116433 is a `hidden beast` number, since 2 + 4 + 3 + 11 + 643 + 3 = 666.
It is not a de Polignac number, because 243116433 - 21 = 243116431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 243116397 and 243116406.
It is not an unprimeable number, because it can be changed into a prime (243116431) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1929433 + ... + 1929558.
Almost surely, 2243116433 is an apocalyptic number.
It is an amenable number.
243116433 is a deficient number, since it is larger than the sum of its proper divisors (158218735).
243116433 is a wasteful number, since it uses less digits than its factorization.
243116433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3859004 (or 3859001 counting only the distinct ones).
The product of its digits is 5184, while the sum is 27.
The square root of 243116433 is about 15592.1914110878. The cubic root of 243116433 is about 624.1247978326.
Adding to 243116433 its reverse (334611342), we get a palindrome (577727775).
The spelling of 243116433 in words is "two hundred forty-three million, one hundred sixteen thousand, four hundred thirty-three".
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