Base | Representation |
---|---|
bin | 1110001001101100011… |
… | …0101110111011010011 |
3 | 212020112110221002000012 |
4 | 3202123012232323103 |
5 | 12440402310332011 |
6 | 303404333545135 |
7 | 23364515215055 |
oct | 3423306567323 |
9 | 766473832005 |
10 | 243120402131 |
11 | 9411a146582 |
12 | 3b1506451ab |
13 | 19c069c0c19 |
14 | baa4c778d5 |
15 | 64cdd84a8b |
hex | 389b1aeed3 |
243120402131 has 2 divisors, whose sum is σ = 243120402132. Its totient is φ = 243120402130.
The previous prime is 243120402121. The next prime is 243120402157. The reversal of 243120402131 is 131204021342.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243120402131 is a prime.
It is a super-2 number, since 2×2431204021312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243120402097 and 243120402106.
It is not a weakly prime, because it can be changed into another prime (243120402121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560201065 + 121560201066.
It is an arithmetic number, because the mean of its divisors is an integer number (121560201066).
Almost surely, 2243120402131 is an apocalyptic number.
243120402131 is a deficient number, since it is larger than the sum of its proper divisors (1).
243120402131 is an equidigital number, since it uses as much as digits as its factorization.
243120402131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 243120402131 its reverse (131204021342), we get a palindrome (374324423473).
The spelling of 243120402131 in words is "two hundred forty-three billion, one hundred twenty million, four hundred two thousand, one hundred thirty-one".
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