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243121014007 is a prime number
BaseRepresentation
bin1110001001101100100…
…1000100010011110111
3212020112112002011100021
43202123021010103313
512440402434422012
6303404355030011
723364523344004
oct3423311042367
9766475064307
10243121014007
119411a524263
123b15089b307
1319c06b76591
14baa4d968ab
1564cde56007
hex389b2444f7

243121014007 has 2 divisors, whose sum is σ = 243121014008. Its totient is φ = 243121014006.

The previous prime is 243121013983. The next prime is 243121014083. The reversal of 243121014007 is 700410121342.

243121014007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 243121014007 - 215 = 243120981239 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243121014107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560507003 + 121560507004.

It is an arithmetic number, because the mean of its divisors is an integer number (121560507004).

Almost surely, 2243121014007 is an apocalyptic number.

243121014007 is a deficient number, since it is larger than the sum of its proper divisors (1).

243121014007 is an equidigital number, since it uses as much as digits as its factorization.

243121014007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 243121014007 its reverse (700410121342), we get a palindrome (943531135349).

The spelling of 243121014007 in words is "two hundred forty-three billion, one hundred twenty-one million, fourteen thousand, seven".