Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1011001110100100001 |
3 | 212020112112020122012110 |
4 | 3202123021121310201 |
5 | 12440403000231423 |
6 | 303404400545533 |
7 | 23364524161611 |
oct | 3423311316441 |
9 | 766475218173 |
10 | 243121102113 |
11 | 9411a58447a |
12 | 3b1509222a9 |
13 | 19c06ba7706 |
14 | baa4dbaa41 |
15 | 64cde72193 |
hex | 389b259d21 |
243121102113 has 4 divisors (see below), whose sum is σ = 324161469488. Its totient is φ = 162080734740.
The previous prime is 243121102111. The next prime is 243121102141. The reversal of 243121102113 is 311201121342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 243121102113 - 21 = 243121102111 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 243121102113.
It is not an unprimeable number, because it can be changed into a prime (243121102111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40520183683 + ... + 40520183688.
It is an arithmetic number, because the mean of its divisors is an integer number (81040367372).
Almost surely, 2243121102113 is an apocalyptic number.
It is an amenable number.
243121102113 is a deficient number, since it is larger than the sum of its proper divisors (81040367375).
243121102113 is an equidigital number, since it uses as much as digits as its factorization.
243121102113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81040367374.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 243121102113 its reverse (311201121342), we get a palindrome (554322223455).
The spelling of 243121102113 in words is "two hundred forty-three billion, one hundred twenty-one million, one hundred two thousand, one hundred thirteen".
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