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2431211114013 = 311227324550943
BaseRepresentation
bin100011011000001111011…
…110011000111000011101
322121102101021122002102120
4203120033132120320131
5304313110021122023
65100514415413153
7340435451332413
oct43301736307035
98542337562376
102431211114013
11858086324090
123332278241b9
131483541508c6
1485957c812b3
15433949d38e3
hex2360f798e1d

2431211114013 has 16 divisors (see below), whose sum is σ = 3551885531136. Its totient is φ = 1466970257840.

The previous prime is 2431211113937. The next prime is 2431211114023. The reversal of 2431211114013 is 3104111121342.

It is a cyclic number.

It is not a de Polignac number, because 2431211114013 - 214 = 2431211097629 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2431211114023) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 162267981 + ... + 162282962.

It is an arithmetic number, because the mean of its divisors is an integer number (221992845696).

Almost surely, 22431211114013 is an apocalyptic number.

It is an amenable number.

2431211114013 is a deficient number, since it is larger than the sum of its proper divisors (1120674417123).

2431211114013 is a wasteful number, since it uses less digits than its factorization.

2431211114013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 324551184.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 2431211114013 its reverse (3104111121342), we get a palindrome (5535322235355).

The spelling of 2431211114013 in words is "two trillion, four hundred thirty-one billion, two hundred eleven million, one hundred fourteen thousand, thirteen".

Divisors: 1 3 11 33 227 681 2497 7491 324550943 973652829 3570060373 10710181119 73673064061 221019192183 810403704671 2431211114013