Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1110101000100000111 |
3 | 212020112112110022021102 |
4 | 3202123021311010013 |
5 | 12440403012314303 |
6 | 303404403210315 |
7 | 23364525135134 |
oct | 3423311650407 |
9 | 766475408242 |
10 | 243121213703 |
11 | 9411a6502a5 |
12 | 3b15097699b |
13 | 19c06c16444 |
14 | baa500958b |
15 | 64cde95288 |
hex | 389b275107 |
243121213703 has 2 divisors, whose sum is σ = 243121213704. Its totient is φ = 243121213702.
The previous prime is 243121213693. The next prime is 243121213711. The reversal of 243121213703 is 307312121342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243121213703 - 210 = 243121212679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243121213733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560606851 + 121560606852.
It is an arithmetic number, because the mean of its divisors is an integer number (121560606852).
Almost surely, 2243121213703 is an apocalyptic number.
243121213703 is a deficient number, since it is larger than the sum of its proper divisors (1).
243121213703 is an equidigital number, since it uses as much as digits as its factorization.
243121213703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 243121213703 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred thirteen thousand, seven hundred three".
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