Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1111011110011101011 |
3 | 212020112112111201011101 |
4 | 3202123021323303223 |
5 | 12440403014210243 |
6 | 303404403542231 |
7 | 23364525311512 |
oct | 3423311736353 |
9 | 766475451141 |
10 | 243121241323 |
11 | 9411a66a024 |
12 | 3b15098a977 |
13 | 19c06c25b9c |
14 | baa5015679 |
15 | 64cde9d54d |
hex | 389b27bceb |
243121241323 has 2 divisors, whose sum is σ = 243121241324. Its totient is φ = 243121241322.
The previous prime is 243121241317. The next prime is 243121241339. The reversal of 243121241323 is 323142121342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 243121241323 - 229 = 242584370411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243121241291 and 243121241300.
It is not a weakly prime, because it can be changed into another prime (243121241383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560620661 + 121560620662.
It is an arithmetic number, because the mean of its divisors is an integer number (121560620662).
Almost surely, 2243121241323 is an apocalyptic number.
243121241323 is a deficient number, since it is larger than the sum of its proper divisors (1).
243121241323 is an equidigital number, since it uses as much as digits as its factorization.
243121241323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 28.
Adding to 243121241323 its reverse (323142121342), we get a palindrome (566263362665).
The spelling of 243121241323 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred forty-one thousand, three hundred twenty-three".
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