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243121244557 is a prime number
BaseRepresentation
bin1110001001101100100…
…1111100100110001101
3212020112112111212121011
43202123021330212031
512440403014311212
6303404404005221
723364525324112
oct3423311744615
9766475455534
10243121244557
119411a6714a4
123b150990811
1319c06c274b9
14baa5016909
1564cde9e4a7
hex389b27c98d

243121244557 has 2 divisors, whose sum is σ = 243121244558. Its totient is φ = 243121244556.

The previous prime is 243121244417. The next prime is 243121244617. The reversal of 243121244557 is 755442121342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 237938108521 + 5183136036 = 487789^2 + 71994^2 .

It is a cyclic number.

It is not a de Polignac number, because 243121244557 - 215 = 243121211789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243121244857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560622278 + 121560622279.

It is an arithmetic number, because the mean of its divisors is an integer number (121560622279).

Almost surely, 2243121244557 is an apocalyptic number.

It is an amenable number.

243121244557 is a deficient number, since it is larger than the sum of its proper divisors (1).

243121244557 is an equidigital number, since it uses as much as digits as its factorization.

243121244557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 268800, while the sum is 40.

Adding to 243121244557 its reverse (755442121342), we get a palindrome (998563365899).

The spelling of 243121244557 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred forty-four thousand, five hundred fifty-seven".