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24312141102131 is a prime number
BaseRepresentation
bin1011000011100100111001…
…00010001011110000110011
310012002012212220201010102022
411201302130202023300303
511141312231110232011
6123412502103142055
75056331343434531
oct541623442136063
9105065786633368
1024312141102131
1178237a2921703
122887a32a4492b
13107481837776c
146009dcd6b151
152c26343438db
hex161c9c88bc33

24312141102131 has 2 divisors, whose sum is σ = 24312141102132. Its totient is φ = 24312141102130.

The previous prime is 24312141102101. The next prime is 24312141102149. The reversal of 24312141102131 is 13120114121342.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24312141102131 is a prime.

It is a super-2 number, since 2×243121411021312 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 24312141102131.

It is not a weakly prime, because it can be changed into another prime (24312141102101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12156070551065 + 12156070551066.

It is an arithmetic number, because the mean of its divisors is an integer number (12156070551066).

Almost surely, 224312141102131 is an apocalyptic number.

24312141102131 is a deficient number, since it is larger than the sum of its proper divisors (1).

24312141102131 is an equidigital number, since it uses as much as digits as its factorization.

24312141102131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 24312141102131 its reverse (13120114121342), we get a palindrome (37432255223473).

The spelling of 24312141102131 in words is "twenty-four trillion, three hundred twelve billion, one hundred forty-one million, one hundred two thousand, one hundred thirty-one".