Base | Representation |
---|---|
bin | 1110001001101100110… |
… | …1000010000110011101 |
3 | 212020112121000222022020 |
4 | 3202123031002012131 |
5 | 12440403221203113 |
6 | 303404433210353 |
7 | 23364535233462 |
oct | 3423315020635 |
9 | 766477028266 |
10 | 243122053533 |
11 | 94120074277 |
12 | 3b1511009b9 |
13 | 19c0714b798 |
14 | baa5187669 |
15 | 64ce0ae023 |
hex | 389b34219d |
243122053533 has 4 divisors (see below), whose sum is σ = 324162738048. Its totient is φ = 162081369020.
The previous prime is 243122053481. The next prime is 243122053549. The reversal of 243122053533 is 335350221342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 243122053533 - 220 = 243121004957 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243122053494 and 243122053503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243122053553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40520342253 + ... + 40520342258.
It is an arithmetic number, because the mean of its divisors is an integer number (81040684512).
Almost surely, 2243122053533 is an apocalyptic number.
It is an amenable number.
243122053533 is a deficient number, since it is larger than the sum of its proper divisors (81040684515).
243122053533 is an equidigital number, since it uses as much as digits as its factorization.
243122053533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81040684514.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 243122053533 its reverse (335350221342), we get a palindrome (578472274875).
The spelling of 243122053533 in words is "two hundred forty-three billion, one hundred twenty-two million, fifty-three thousand, five hundred thirty-three".
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