243122421410131 has 8 divisors (see below), whose sum is σ = 245305633192704. Its totient is φ = 240939765521280.

The previous prime is 243122421410051. The next prime is 243122421410149. The reversal of 243122421410131 is 131014124221342.

243122421410131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 243122421410131 - 2³¹ = 243120273926483 is a prime.

It is a super-2 number, since 2×243122421410131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243122421410093 and 243122421410102.

It is not an unprimeable number, because it can be changed into a prime (243122421410161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 138094771 + ... + 139844236.

It is an arithmetic number, because the mean of its divisors is an integer number (30663204149088).

Almost surely, 2^{243122421410131} is an apocalyptic number.

243122421410131 is a deficient number, since it is larger than the sum of its proper divisors (2183211782573).

243122421410131 is a wasteful number, since it uses less digits than its factorization.

243122421410131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 277946861.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 243122421410131 its reverse (131014124221342), we get a palindrome (374136545631473).

The spelling of 243122421410131 in words is "two hundred forty-three trillion, one hundred twenty-two billion, four hundred twenty-one million, four hundred ten thousand, one hundred thirty-one".