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243122421410149 is a prime number
BaseRepresentation
bin110111010001111001011001…
…100100001010100101100101
31011212211021110120022100002211
4313101321121210022211211
5223331304204340111044
62221024522025003421
7102132005150425561
oct6721713144124545
91155737416270084
10243122421410149
1170514704774526
1223326907023571
13a587466114768
14440728bb726a1
151d1928ad5a634
hexdd1e5990a965

243122421410149 has 2 divisors, whose sum is σ = 243122421410150. Its totient is φ = 243122421410148.

The previous prime is 243122421410051. The next prime is 243122421410161. The reversal of 243122421410149 is 941014124221342.

243122421410149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 243009126562500 + 113294847649 = 15588750^2 + 336593^2 .

It is a cyclic number.

It is not a de Polignac number, because 243122421410149 - 243 = 234326328387941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243122421410249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121561210705074 + 121561210705075.

It is an arithmetic number, because the mean of its divisors is an integer number (121561210705075).

Almost surely, 2243122421410149 is an apocalyptic number.

It is an amenable number.

243122421410149 is a deficient number, since it is larger than the sum of its proper divisors (1).

243122421410149 is an equidigital number, since it uses as much as digits as its factorization.

243122421410149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 40.

The spelling of 243122421410149 in words is "two hundred forty-three trillion, one hundred twenty-two billion, four hundred twenty-one million, four hundred ten thousand, one hundred forty-nine".