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243125112215039 is a prime number
BaseRepresentation
bin110111010001111011111001…
…111100110001010111111111
31011212211112102002112101111012
4313101323321330301113333
5223331330212211340124
62221030045030145435
7102132131633044025
oct6721737174612777
91155745362471435
10243125112215039
117051586565001a
12233273381b227b
13a5877a472bac2
144407465290715
151d193971c5e0e
hexdd1ef9f315ff

243125112215039 has 2 divisors, whose sum is σ = 243125112215040. Its totient is φ = 243125112215038.

The previous prime is 243125112215017. The next prime is 243125112215081. The reversal of 243125112215039 is 930512211521342.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-243125112215039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 243125112214987 and 243125112215005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243125112215539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121562556107519 + 121562556107520.

It is an arithmetic number, because the mean of its divisors is an integer number (121562556107520).

Almost surely, 2243125112215039 is an apocalyptic number.

243125112215039 is a deficient number, since it is larger than the sum of its proper divisors (1).

243125112215039 is an equidigital number, since it uses as much as digits as its factorization.

243125112215039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 243125112215039 in words is "two hundred forty-three trillion, one hundred twenty-five billion, one hundred twelve million, two hundred fifteen thousand, thirty-nine".