243125112215041 has 4 divisors (see below), whose sum is σ = 277857271102912. Its totient is φ = 208392953327172.

The previous prime is 243125112215039. The next prime is 243125112215081. The reversal of 243125112215041 is 140512211521342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 243125112215041 - 2¹ = 243125112215039 is a prime.

It is a super-3 number, since 3×243125112215041³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243125112214988 and 243125112215006.

It is not an unprimeable number, because it can be changed into a prime (243125112215081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17366079443925 + ... + 17366079443938.

It is an arithmetic number, because the mean of its divisors is an integer number (69464317775728).

Almost surely, 2^{243125112215041} is an apocalyptic number.

It is an amenable number.

243125112215041 is a deficient number, since it is larger than the sum of its proper divisors (34732158887871).

243125112215041 is an equidigital number, since it uses as much as digits as its factorization.

243125112215041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34732158887870.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 243125112215041 its reverse (140512211521342), we get a palindrome (383637323736383).

The spelling of 243125112215041 in words is "two hundred forty-three trillion, one hundred twenty-five billion, one hundred twelve million, two hundred fifteen thousand, forty-one".