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2431300440343 = 10922305508627
BaseRepresentation
bin100011011000010100110…
…011001001000100010111
322121102121111201100010011
4203120110303021010113
5304313300403042333
65100531330141051
7340440614521135
oct43302463110427
98542544640104
102431300440343
118581217952a5
12333251721787
131483697c8018
1485965a94755
154339c77a9cd
hex23614cc9117

2431300440343 has 4 divisors (see below), whose sum is σ = 2453605949080. Its totient is φ = 2408994931608.

The previous prime is 2431300440323. The next prime is 2431300440347. The reversal of 2431300440343 is 3430440031342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2431300440343 - 213 = 2431300432151 is a prime.

It is a super-2 number, since 2×24313004403432 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2431300440347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11152754205 + ... + 11152754422.

It is an arithmetic number, because the mean of its divisors is an integer number (613401487270).

Almost surely, 22431300440343 is an apocalyptic number.

2431300440343 is a deficient number, since it is larger than the sum of its proper divisors (22305508737).

2431300440343 is a wasteful number, since it uses less digits than its factorization.

2431300440343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22305508736.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 2431300440343 its reverse (3430440031342), we get a palindrome (5861740471685).

The spelling of 2431300440343 in words is "two trillion, four hundred thirty-one billion, three hundred million, four hundred forty thousand, three hundred forty-three".

Divisors: 1 109 22305508627 2431300440343