243131114003 has 4 divisors (see below), whose sum is σ = 243139816920. Its totient is φ = 243122411088.

The previous prime is 243131113873. The next prime is 243131114071. The reversal of 243131114003 is 300411131342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243131114003 - 2¹⁰ = 243131112979 is a prime.

It is a super-2 number, since 2×243131114003² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 243131114003.

It is not an unprimeable number, because it can be changed into a prime (243161114003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4309418 + ... + 4365471.

It is an arithmetic number, because the mean of its divisors is an integer number (60784954230).

Almost surely, 2^243131114003 is an apocalyptic number.

243131114003 is a deficient number, since it is larger than the sum of its proper divisors (8702917).

243131114003 is an equidigital number, since it uses as much as digits as its factorization.

243131114003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8702916.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 243131114003 its reverse (300411131342), we get a palindrome (543542245345).

The spelling of 243131114003 in words is "two hundred forty-three billion, one hundred thirty-one million, one hundred fourteen thousand, three".