2431314240137 has 2 divisors, whose sum is σ = 2431314240138. Its totient is φ = 2431314240136.

The previous prime is 2431314240109. The next prime is 2431314240139. The reversal of 2431314240137 is 7310424131342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1944027872656 + 487286367481 = 1394284^2 + 698059^2 .

It is a cyclic number.

It is not a de Polignac number, because 2431314240137 - 2³² = 2427019272841 is a prime.

It is a super-2 number, since 2×2431314240137² (a number of 26 digits) contains 22 as substring.

Together with 2431314240139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2431314240097 and 2431314240106.

It is not a weakly prime, because it can be changed into another prime (2431314240139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1215657120068 + 1215657120069.

It is an arithmetic number, because the mean of its divisors is an integer number (1215657120069).

Almost surely, 2^{2431314240137} is an apocalyptic number.

It is an amenable number.

2431314240137 is a deficient number, since it is larger than the sum of its proper divisors (1).

2431314240137 is an equidigital number, since it uses as much as digits as its factorization.

2431314240137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 2431314240137 its reverse (7310424131342), we get a palindrome (9741738371479).

The spelling of 2431314240137 in words is "two trillion, four hundred thirty-one billion, three hundred fourteen million, two hundred forty thousand, one hundred thirty-seven".