Base | Representation |
---|---|
bin | 1110001001110001001… |
… | …1011100111010011001 |
3 | 212020120212202211112020 |
4 | 3202130103130322121 |
5 | 12440422432412213 |
6 | 303410333005053 |
7 | 23365151156436 |
oct | 3423423347231 |
9 | 766525684466 |
10 | 243140513433 |
11 | 9412a532494 |
12 | 3b157323789 |
13 | 19c0ac12bbc |
14 | baa77d0b8d |
15 | 64d0a08923 |
hex | 389c4dce99 |
243140513433 has 8 divisors (see below), whose sum is σ = 338282453568. Its totient is φ = 155046124464.
The previous prime is 243140513419. The next prime is 243140513459. The reversal of 243140513433 is 334315041342.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 243140513433 - 210 = 243140512409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243140513394 and 243140513403.
It is not an unprimeable number, because it can be changed into a prime (243140513933) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1761887710 + ... + 1761887847.
It is an arithmetic number, because the mean of its divisors is an integer number (42285306696).
Almost surely, 2243140513433 is an apocalyptic number.
243140513433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
243140513433 is a deficient number, since it is larger than the sum of its proper divisors (95141940135).
243140513433 is a wasteful number, since it uses less digits than its factorization.
243140513433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3523775583.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 243140513433 its reverse (334315041342), we get a palindrome (577455554775).
The spelling of 243140513433 in words is "two hundred forty-three billion, one hundred forty million, five hundred thirteen thousand, four hundred thirty-three".
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