Base | Representation |
---|---|
bin | 1110001001111111011… |
… | …0110011110101011101 |
3 | 212020202000220212011010 |
4 | 3202133312303311131 |
5 | 12441033212122023 |
6 | 303420302245433 |
7 | 23366503601163 |
oct | 3423766636535 |
9 | 766660825133 |
10 | 243200114013 |
11 | 9416014026a |
12 | 3b173286879 |
13 | 19c1a38010c |
14 | bab16a7233 |
15 | 64d5d7d093 |
hex | 389fdb3d5d |
243200114013 has 4 divisors (see below), whose sum is σ = 324266818688. Its totient is φ = 162133409340.
The previous prime is 243200114009. The next prime is 243200114051. The reversal of 243200114013 is 310411002342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 243200114013 - 22 = 243200114009 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243200114093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40533352333 + ... + 40533352338.
It is an arithmetic number, because the mean of its divisors is an integer number (81066704672).
Almost surely, 2243200114013 is an apocalyptic number.
It is an amenable number.
243200114013 is a deficient number, since it is larger than the sum of its proper divisors (81066704675).
243200114013 is an equidigital number, since it uses as much as digits as its factorization.
243200114013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81066704674.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 243200114013 its reverse (310411002342), we get a palindrome (553611116355).
The spelling of 243200114013 in words is "two hundred forty-three billion, two hundred million, one hundred fourteen thousand, thirteen".
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