Base | Representation |
---|---|
bin | 10110101001100101… |
… | …110111001100111101 |
3 | 2022202220120200000110 |
4 | 112221211313030331 |
5 | 344301422031141 |
6 | 15101132220233 |
7 | 1520450351634 |
oct | 265145671475 |
9 | 68686520013 |
10 | 24320111421 |
11 | a350083741 |
12 | 486890a679 |
13 | 23a7719198 |
14 | 1269d6651b |
15 | 975173e16 |
hex | 5a997733d |
24320111421 has 4 divisors (see below), whose sum is σ = 32426815232. Its totient is φ = 16213407612.
The previous prime is 24320111419. The next prime is 24320111423. The reversal of 24320111421 is 12411102342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (24320111419) and next prime (24320111423).
It is not a de Polignac number, because 24320111421 - 21 = 24320111419 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (24320111423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4053351901 + ... + 4053351906.
It is an arithmetic number, because the mean of its divisors is an integer number (8106703808).
Almost surely, 224320111421 is an apocalyptic number.
It is an amenable number.
24320111421 is a deficient number, since it is larger than the sum of its proper divisors (8106703811).
24320111421 is an equidigital number, since it uses as much as digits as its factorization.
24320111421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8106703810.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 24320111421 its reverse (12411102342), we get a palindrome (36731213763).
The spelling of 24320111421 in words is "twenty-four billion, three hundred twenty million, one hundred eleven thousand, four hundred twenty-one".
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