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243201150497 is a prime number
BaseRepresentation
bin1110001001111111101…
…0110000111000100001
3212020202002212111221102
43202133322300320201
512441033443303442
6303420340404145
723366515446044
oct3423772607041
9766662774842
10243201150497
1194160788a68
123b1736a6655
1319c1a653b16
14bab1896c5b
1564d5ed5232
hex389feb0e21

243201150497 has 2 divisors, whose sum is σ = 243201150498. Its totient is φ = 243201150496.

The previous prime is 243201150433. The next prime is 243201150499. The reversal of 243201150497 is 794051102342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 191689854976 + 51511295521 = 437824^2 + 226961^2 .

It is a cyclic number.

It is not a de Polignac number, because 243201150497 - 26 = 243201150433 is a prime.

Together with 243201150499, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 243201150497.

It is not a weakly prime, because it can be changed into another prime (243201150499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121600575248 + 121600575249.

It is an arithmetic number, because the mean of its divisors is an integer number (121600575249).

Almost surely, 2243201150497 is an apocalyptic number.

It is an amenable number.

243201150497 is a deficient number, since it is larger than the sum of its proper divisors (1).

243201150497 is an equidigital number, since it uses as much as digits as its factorization.

243201150497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 38.

The spelling of 243201150497 in words is "two hundred forty-three billion, two hundred one million, one hundred fifty thousand, four hundred ninety-seven".