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2432012000000 = 285611311783
BaseRepresentation
bin100011011000111111001…
…101100001101100000000
322121111110002122022110112
4203120333031201230000
5304321230033000000
65101130105250452
7340464344626112
oct43307715415400
98544402568415
102432012000000
1185845740a630
1233340ba93a28
13148451053b3b
14859d239b3b2
15433dee83235
hex2363f361b00

2432012000000 has 504 divisors, whose sum is σ = 6837092484096. Its totient is φ = 855360000000.

The previous prime is 2432011999999. The next prime is 2432012000017. The reversal of 2432012000000 is 2102342.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 1363999109 + ... + 1364000891.

Almost surely, 22432012000000 is an apocalyptic number.

2432012000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2432012000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3418546242048).

2432012000000 is an abundant number, since it is smaller than the sum of its proper divisors (4405080484096).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2432012000000 is an frugal number, since it uses more digits than its factorization.

2432012000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1871 (or 1832 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 14.

Adding to 2432012000000 its reverse (2102342), we get a palindrome (2432014102342).

The spelling of 2432012000000 in words is "two trillion, four hundred thirty-two billion, twelve million", and thus it is an aban number.