Base | Representation |
---|---|
bin | 1110001010000000001… |
… | …0010000001000101001 |
3 | 212020202020120020200201 |
4 | 3202200002100020221 |
5 | 12441034444113023 |
6 | 303420450432201 |
7 | 23366541233113 |
oct | 3424002201051 |
9 | 766666506621 |
10 | 243203113513 |
11 | 941618a9898 |
12 | 3b174292661 |
13 | 19c1ab90479 |
14 | bab1c483b3 |
15 | 64d6271bad |
hex | 38a0090229 |
243203113513 has 2 divisors, whose sum is σ = 243203113514. Its totient is φ = 243203113512.
The previous prime is 243203113423. The next prime is 243203113547. The reversal of 243203113513 is 315311302342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131049792064 + 112153321449 = 362008^2 + 334893^2 .
It is a cyclic number.
It is not a de Polignac number, because 243203113513 - 221 = 243201016361 is a prime.
It is not a weakly prime, because it can be changed into another prime (243203113553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121601556756 + 121601556757.
It is an arithmetic number, because the mean of its divisors is an integer number (121601556757).
Almost surely, 2243203113513 is an apocalyptic number.
It is an amenable number.
243203113513 is a deficient number, since it is larger than the sum of its proper divisors (1).
243203113513 is an equidigital number, since it uses as much as digits as its factorization.
243203113513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 243203113513 its reverse (315311302342), we get a palindrome (558514415855).
The spelling of 243203113513 in words is "two hundred forty-three billion, two hundred three million, one hundred thirteen thousand, five hundred thirteen".
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