Base | Representation |
---|---|
bin | 110111010011011111110001… |
… | …001110110001011110011111 |
3 | 1011220012210011222202102102022 |
4 | 313103133301032301132133 |
5 | 223340104313032342003 |
6 | 2221151221112250355 |
7 | 102142646064155105 |
oct | 6723376116613637 |
9 | 1156183158672368 |
10 | 243232340121503 |
11 | 7055728aa43237 |
12 | 233440826a09bb |
13 | a59493281c875 |
14 | 440c718235c75 |
15 | 1d1c070c47738 |
hex | dd37f13b179f |
243232340121503 has 2 divisors, whose sum is σ = 243232340121504. Its totient is φ = 243232340121502.
The previous prime is 243232340121473. The next prime is 243232340121587. The reversal of 243232340121503 is 305121043232342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 243232340121503 - 26 = 243232340121439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243232340121593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121616170060751 + 121616170060752.
It is an arithmetic number, because the mean of its divisors is an integer number (121616170060752).
Almost surely, 2243232340121503 is an apocalyptic number.
243232340121503 is a deficient number, since it is larger than the sum of its proper divisors (1).
243232340121503 is an equidigital number, since it uses as much as digits as its factorization.
243232340121503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 243232340121503 its reverse (305121043232342), we get a palindrome (548353383353845).
The spelling of 243232340121503 in words is "two hundred forty-three trillion, two hundred thirty-two billion, three hundred forty million, one hundred twenty-one thousand, five hundred three".
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