Base | Representation |
---|---|
bin | 100011011010001100110… |
… | …001010000001100000100 |
3 | 22121121210210002200120201 |
4 | 203122030301100030010 |
5 | 304331411140224030 |
6 | 5101503150540244 |
7 | 340541525012440 |
oct | 43321461201404 |
9 | 8547723080521 |
10 | 2433313211140 |
11 | 858a64964839 |
12 | 333713807684 |
13 | 1485ca7c4166 |
14 | 85ab7115820 |
15 | 434693122ca |
hex | 2368cc50304 |
2433313211140 has 24 divisors (see below), whose sum is σ = 5839951707072. Its totient is φ = 834278815200.
The previous prime is 2433313211129. The next prime is 2433313211281. The reversal of 2433313211140 is 411123133342.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a junction number, because it is equal to n+sod(n) for n = 2433313211099 and 2433313211108.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8690404186 + ... + 8690404465.
It is an arithmetic number, because the mean of its divisors is an integer number (243331321128).
Almost surely, 22433313211140 is an apocalyptic number.
2433313211140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2433313211140 is an abundant number, since it is smaller than the sum of its proper divisors (3406638495932).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2433313211140 is a wasteful number, since it uses less digits than its factorization.
2433313211140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17380808667 (or 17380808665 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 2433313211140 its reverse (411123133342), we get a palindrome (2844436344482).
The spelling of 2433313211140 in words is "two trillion, four hundred thirty-three billion, three hundred thirteen million, two hundred eleven thousand, one hundred forty".
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