Base | Representation |
---|---|
bin | 1110001010101111001… |
… | …0100111001100000111 |
3 | 212021020222200101212222 |
4 | 3202223302213030013 |
5 | 12441440441341411 |
6 | 303452214002555 |
7 | 23404454520116 |
oct | 3425362471407 |
9 | 767228611788 |
10 | 243400340231 |
11 | 94253168184 |
12 | 3b20a34645b |
13 | 19c4c9b6379 |
14 | bad0107c7d |
15 | 64e872e4db |
hex | 38abca7307 |
243400340231 has 2 divisors, whose sum is σ = 243400340232. Its totient is φ = 243400340230.
The previous prime is 243400340179. The next prime is 243400340243. The reversal of 243400340231 is 132043004342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243400340231 - 218 = 243400078087 is a prime.
It is a super-2 number, since 2×2434003402312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 243400340231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243400340291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121700170115 + 121700170116.
It is an arithmetic number, because the mean of its divisors is an integer number (121700170116).
Almost surely, 2243400340231 is an apocalyptic number.
243400340231 is a deficient number, since it is larger than the sum of its proper divisors (1).
243400340231 is an equidigital number, since it uses as much as digits as its factorization.
243400340231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 243400340231 its reverse (132043004342), we get a palindrome (375443344573).
The spelling of 243400340231 in words is "two hundred forty-three billion, four hundred million, three hundred forty thousand, two hundred thirty-one".
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