243413004020231 has 2 divisors, whose sum is σ = 243413004020232. Its totient is φ = 243413004020230.

The previous prime is 243413004020191. The next prime is 243413004020267. The reversal of 243413004020231 is 132020400314342.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243413004020231 - 2⁴² = 239014957509127 is a prime.

It is a super-4 number, since 4×243413004020231⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 243413004020194 and 243413004020203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243413004020531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121706502010115 + 121706502010116.

It is an arithmetic number, because the mean of its divisors is an integer number (121706502010116).

Almost surely, 2^{243413004020231} is an apocalyptic number.

243413004020231 is a deficient number, since it is larger than the sum of its proper divisors (1).

243413004020231 is an equidigital number, since it uses as much as digits as its factorization.

243413004020231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 243413004020231 its reverse (132020400314342), we get a palindrome (375433404334573).

The spelling of 243413004020231 in words is "two hundred forty-three trillion, four hundred thirteen billion, four million, twenty thousand, two hundred thirty-one".