243420441133 has 2 divisors, whose sum is σ = 243420441134. Its totient is φ = 243420441132.

The previous prime is 243420441079. The next prime is 243420441139. The reversal of 243420441133 is 331144024342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 185004934884 + 58415506249 = 430122^2 + 241693^2 .

It is a cyclic number.

It is not a de Polignac number, because 243420441133 - 2⁹ = 243420440621 is a prime.

It is a super-2 number, since 2×243420441133² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 243420441095 and 243420441104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243420441139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121710220566 + 121710220567.

It is an arithmetic number, because the mean of its divisors is an integer number (121710220567).

Almost surely, 2^243420441133 is an apocalyptic number.

It is an amenable number.

243420441133 is a deficient number, since it is larger than the sum of its proper divisors (1).

243420441133 is an equidigital number, since it uses as much as digits as its factorization.

243420441133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 243420441133 its reverse (331144024342), we get a palindrome (574564465475).

The spelling of 243420441133 in words is "two hundred forty-three billion, four hundred twenty million, four hundred forty-one thousand, one hundred thirty-three".