Base | Representation |
---|---|
bin | 100011011011010000000… |
… | …111010000100101011111 |
3 | 22121201201112002121210121 |
4 | 203123100013100211133 |
5 | 304341214410202112 |
6 | 5102211231215411 |
7 | 340611524346301 |
oct | 43332007204537 |
9 | 8551645077717 |
10 | 2434443053407 |
11 | 859494701a82 |
12 | 33398a077567 |
13 | 14874a8c3091 |
14 | 85b831c1971 |
15 | 434d35e0407 |
hex | 236d01d095f |
2434443053407 has 2 divisors, whose sum is σ = 2434443053408. Its totient is φ = 2434443053406.
The previous prime is 2434443053389. The next prime is 2434443053447. The reversal of 2434443053407 is 7043503444342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2434443053407 - 27 = 2434443053279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2434443053447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1217221526703 + 1217221526704.
It is an arithmetic number, because the mean of its divisors is an integer number (1217221526704).
Almost surely, 22434443053407 is an apocalyptic number.
2434443053407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2434443053407 is an equidigital number, since it uses as much as digits as its factorization.
2434443053407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1935360, while the sum is 43.
Adding to 2434443053407 its reverse (7043503444342), we get a palindrome (9477946497749).
The spelling of 2434443053407 in words is "two trillion, four hundred thirty-four billion, four hundred forty-three million, fifty-three thousand, four hundred seven".
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