243540004140493 has 2 divisors, whose sum is σ = 243540004140494. Its totient is φ = 243540004140492.

The previous prime is 243540004140397. The next prime is 243540004140509. The reversal of 243540004140493 is 394041400045342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 235435973029929 + 8104031110564 = 15343923^2 + 2846758^2 .

It is a cyclic number.

It is not a de Polignac number, because 243540004140493 - 2¹³ = 243540004132301 is a prime.

It is a super-3 number, since 3×243540004140493³ (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243540004240493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121770002070246 + 121770002070247.

It is an arithmetic number, because the mean of its divisors is an integer number (121770002070247).

Almost surely, 2^{243540004140493} is an apocalyptic number.

It is an amenable number.

243540004140493 is a deficient number, since it is larger than the sum of its proper divisors (1).

243540004140493 is an equidigital number, since it uses as much as digits as its factorization.

243540004140493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 829440, while the sum is 43.

The spelling of 243540004140493 in words is "two hundred forty-three trillion, five hundred forty billion, four million, one hundred forty thousand, four hundred ninety-three".