Base | Representation |
---|---|
bin | 1001000101010010… |
… | …1011010001010001 |
3 | 20021220202010222122 |
4 | 2101110223101101 |
5 | 14443124211213 |
6 | 1041533144025 |
7 | 114263435114 |
oct | 22124532121 |
9 | 6256663878 |
10 | 2438116433 |
11 | 1041286a65 |
12 | 58062b015 |
13 | 2cb17305c |
14 | 191b4257b |
15 | e40a4d08 |
hex | 9152b451 |
2438116433 has 2 divisors, whose sum is σ = 2438116434. Its totient is φ = 2438116432.
The previous prime is 2438116393. The next prime is 2438116459. The reversal of 2438116433 is 3346118342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2387592769 + 50523664 = 48863^2 + 7108^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2438116433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2438116393 and 2438116402.
It is not a weakly prime, because it can be changed into another prime (2438116133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1219058216 + 1219058217.
It is an arithmetic number, because the mean of its divisors is an integer number (1219058217).
Almost surely, 22438116433 is an apocalyptic number.
It is an amenable number.
2438116433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2438116433 is an equidigital number, since it uses as much as digits as its factorization.
2438116433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 35.
The square root of 2438116433 is about 49377.2866103434. The cubic root of 2438116433 is about 1345.9165926869.
The spelling of 2438116433 in words is "two billion, four hundred thirty-eight million, one hundred sixteen thousand, four hundred thirty-three".
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