Base | Representation |
---|---|
bin | 100011100000100010000… |
… | …100110010100011011001 |
3 | 22122021100200022002111122 |
4 | 203200202010302203121 |
5 | 304434322423330423 |
6 | 5104550020135025 |
7 | 341202164113265 |
oct | 43404204624331 |
9 | 8567320262448 |
10 | 2440113105113 |
11 | 860934263822 |
12 | 334ab0b37475 |
13 | 149142506768 |
14 | 861602630a5 |
15 | 437162a08c8 |
hex | 238221328d9 |
2440113105113 has 2 divisors, whose sum is σ = 2440113105114. Its totient is φ = 2440113105112.
The previous prime is 2440113105097. The next prime is 2440113105139. The reversal of 2440113105113 is 3115013110442.
It is an a-pointer prime, because the next prime (2440113105139) can be obtained adding 2440113105113 to its sum of digits (26).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1989941886409 + 450171218704 = 1410653^2 + 670948^2 .
It is a cyclic number.
It is not a de Polignac number, because 2440113105113 - 24 = 2440113105097 is a prime.
It is not a weakly prime, because it can be changed into another prime (2440113105613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1220056552556 + 1220056552557.
It is an arithmetic number, because the mean of its divisors is an integer number (1220056552557).
Almost surely, 22440113105113 is an apocalyptic number.
It is an amenable number.
2440113105113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2440113105113 is an equidigital number, since it uses as much as digits as its factorization.
2440113105113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 2440113105113 its reverse (3115013110442), we get a palindrome (5555126215555).
The spelling of 2440113105113 in words is "two trillion, four hundred forty billion, one hundred thirteen million, one hundred five thousand, one hundred thirteen".
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