Base | Representation |
---|---|
bin | 110111011110110110000000… |
… | …011101101001101111000111 |
3 | 1011222222022222001012122102002 |
4 | 313132312000131221233013 |
5 | 223440343321323310143 |
6 | 2222545343115535515 |
7 | 102253203052640444 |
oct | 6736660035515707 |
9 | 1158868861178362 |
10 | 244012132244423 |
11 | 70827a672a5874 |
12 | 2344b22945a59b |
13 | a620326009b0a |
14 | 44383708429cb |
15 | 1d324aee0a5b8 |
hex | dded80769bc7 |
244012132244423 has 2 divisors, whose sum is σ = 244012132244424. Its totient is φ = 244012132244422.
The previous prime is 244012132244407. The next prime is 244012132244471. The reversal of 244012132244423 is 324442231210442.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 244012132244423 - 24 = 244012132244407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244012132244123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122006066122211 + 122006066122212.
It is an arithmetic number, because the mean of its divisors is an integer number (122006066122212).
Almost surely, 2244012132244423 is an apocalyptic number.
244012132244423 is a deficient number, since it is larger than the sum of its proper divisors (1).
244012132244423 is an equidigital number, since it uses as much as digits as its factorization.
244012132244423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294912, while the sum is 38.
Adding to 244012132244423 its reverse (324442231210442), we get a palindrome (568454363454865).
The spelling of 244012132244423 in words is "two hundred forty-four trillion, twelve billion, one hundred thirty-two million, two hundred forty-four thousand, four hundred twenty-three".
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