Base | Representation |
---|---|
bin | 110111011110110110010001… |
… | …100111101111001111101111 |
3 | 1011222222100201002212021112121 |
4 | 313132312101213233033233 |
5 | 223440344414021213403 |
6 | 2222545431441413411 |
7 | 102253213146452653 |
oct | 6736662147571757 |
9 | 1158870632767477 |
10 | 244012420101103 |
11 | 708280a4835855 |
12 | 2344b2a993a267 |
13 | a620370845604 |
14 | 443839ab74a63 |
15 | 1d324ca31b3bd |
hex | dded919ef3ef |
244012420101103 has 2 divisors, whose sum is σ = 244012420101104. Its totient is φ = 244012420101102.
The previous prime is 244012420101083. The next prime is 244012420101127. The reversal of 244012420101103 is 301101024210442.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 244012420101103 - 25 = 244012420101071 is a prime.
It is a super-2 number, since 2×2440124201011032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244012420108103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122006210050551 + 122006210050552.
It is an arithmetic number, because the mean of its divisors is an integer number (122006210050552).
Almost surely, 2244012420101103 is an apocalyptic number.
244012420101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
244012420101103 is an equidigital number, since it uses as much as digits as its factorization.
244012420101103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 244012420101103 its reverse (301101024210442), we get a palindrome (545113444311545).
The spelling of 244012420101103 in words is "two hundred forty-four trillion, twelve billion, four hundred twenty million, one hundred one thousand, one hundred three".
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