Base | Representation |
---|---|
bin | 110111011110111000001110… |
… | …011001001001110111100111 |
3 | 1011222222120002222211101221011 |
4 | 313132320032121021313213 |
5 | 223440413210414224431 |
6 | 2222550415301003051 |
7 | 102253316055453433 |
oct | 6736701631116747 |
9 | 1158876088741834 |
10 | 244014513429991 |
11 | 70828a79427827 |
12 | 2344b7929b3487 |
13 | a620615438b65 |
14 | 4438518ba59c3 |
15 | 1d3259deb6cb1 |
hex | ddee0e649de7 |
244014513429991 has 2 divisors, whose sum is σ = 244014513429992. Its totient is φ = 244014513429990.
The previous prime is 244014513429913. The next prime is 244014513430027. The reversal of 244014513429991 is 199924315410442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 244014513429991 - 211 = 244014513427943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244014513420991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122007256714995 + 122007256714996.
It is an arithmetic number, because the mean of its divisors is an integer number (122007256714996).
Almost surely, 2244014513429991 is an apocalyptic number.
244014513429991 is a deficient number, since it is larger than the sum of its proper divisors (1).
244014513429991 is an equidigital number, since it uses as much as digits as its factorization.
244014513429991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11197440, while the sum is 58.
The spelling of 244014513429991 in words is "two hundred forty-four trillion, fourteen billion, five hundred thirteen million, four hundred twenty-nine thousand, nine hundred ninety-one".
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