Base | Representation |
---|---|
bin | 100011100000101001010… |
… | …011111011001111001011 |
3 | 22122021200010202021022012 |
4 | 203200221103323033023 |
5 | 304440100013411410 |
6 | 5105010034250135 |
7 | 341205200061212 |
oct | 43405123731713 |
9 | 8567603667265 |
10 | 2440234513355 |
11 | 860996847611 |
12 | 334b2572694b |
13 | 149161704662 |
14 | 86172428079 |
15 | 43721c83605 |
hex | 238294fb3cb |
2440234513355 has 4 divisors (see below), whose sum is σ = 2928281416032. Its totient is φ = 1952187610680.
The previous prime is 2440234513313. The next prime is 2440234513397. The reversal of 2440234513355 is 5533154320442.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (2440234513313) and next prime (2440234513397).
It is not a de Polignac number, because 2440234513355 - 28 = 2440234513099 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244023451331 + ... + 244023451340.
It is an arithmetic number, because the mean of its divisors is an integer number (732070354008).
Almost surely, 22440234513355 is an apocalyptic number.
2440234513355 is a deficient number, since it is larger than the sum of its proper divisors (488046902677).
2440234513355 is an equidigital number, since it uses as much as digits as its factorization.
2440234513355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488046902676.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 2440234513355 its reverse (5533154320442), we get a palindrome (7973388833797).
The spelling of 2440234513355 in words is "two trillion, four hundred forty billion, two hundred thirty-four million, five hundred thirteen thousand, three hundred fifty-five".
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