Base | Representation |
---|---|
bin | 100011100000101111001… |
… | …001011000100010100001 |
3 | 22122021220221222002111021 |
4 | 203200233021120202201 |
5 | 304440300044204324 |
6 | 5105023452445441 |
7 | 341210466155164 |
oct | 43405711304241 |
9 | 8567827862437 |
10 | 2440332413089 |
11 | 860a3703408a |
12 | 334b52479881 |
13 | 149178a911ac |
14 | 8618142dadb |
15 | 4372a670ae4 |
hex | 2382f2588a1 |
2440332413089 has 2 divisors, whose sum is σ = 2440332413090. Its totient is φ = 2440332413088.
The previous prime is 2440332413033. The next prime is 2440332413149. The reversal of 2440332413089 is 9803142330442.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1981244859489 + 459087553600 = 1407567^2 + 677560^2 .
It is a cyclic number.
It is not a de Polignac number, because 2440332413089 - 227 = 2440198195361 is a prime.
It is not a weakly prime, because it can be changed into another prime (2440332413009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1220166206544 + 1220166206545.
It is an arithmetic number, because the mean of its divisors is an integer number (1220166206545).
Almost surely, 22440332413089 is an apocalyptic number.
It is an amenable number.
2440332413089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2440332413089 is an equidigital number, since it uses as much as digits as its factorization.
2440332413089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 43.
The spelling of 2440332413089 in words is "two trillion, four hundred forty billion, three hundred thirty-two million, four hundred thirteen thousand, eighty-nine".
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